UMBC CMSC201, Computer Science I, Spring 1994 Sections 0101, 0102 and Honors

Midterm Exam, Short Answer Section

Short Answers, 4 points each

There are no intentional syntax errors in this section. Answers like ``There is no output, because there is a syntax error'' will receive 0 credit.

1. What is the output of the following code?

       int i, j ;
       
       for (i = 0 ; i < 5 ; i++) {
          for (j = 0 ; j < 5 ; j++) {
             if ( i * i >= j) {
                printf("X") ;
             } else {
                printf("O") ;
             }
          }
          printf("\n") ;
       }
     

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2. Write down the output of this program. Show your work and clearly indicate your final answer.

       #include <stdio.h>
       #include "genlib.h"
       #include "simpio.h"
       
       int foobar(int a) ;
       int geez(int b) ;
       
       main() {
          int a = 1, b = 2, c = 3 ;
          
          c = geez(a) ;
          b = foobar(c) ;
          printf("main: a = %d, b = %d, c= %d\n", a, b , c) ;
       }
       
       int foobar (int b) {
          int a, c ;
          
          a = geez(b) ;
          c = b++ ;
          printf("foobar: a = %d, b = %d, c = %d\n", a, b, c) ;
          return(c) ;
       }
       
       int geez (int c) {
          int a, b ;
          
          a = c + 100 ;
          b = 2 * a ;
          printf("geez: a = %d, b = %d, c = %d\n", a, b, c) ;     
          return(a) ;
       }
     

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3. Write a simple loop to print out the following numbers. (Hint: this is the first part of the sequence of the squares of odd numbers.)

         1 9 25 49 81 121 169
   

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4. Write a simple function called CubeRoot which takes an int argument n and returns the largest integer whose cube is smaller than n. For example, CubeRoot(9) should return 2 because 2*2*2 = 8 < 9 < 27 = 3*3*3. Similarly, CubeRoot(119) should return 4.

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