/* File: scanf3a.c

   Test use of the scanf() function to read in user input
   What happens if you use %f instead of %lf?

   If you compile this with -Wall, gcc will catch this 
   error for you!!!!
*/

#include <stdio.h>

// Let's make main() return an int. 
int main() {
   int n ;	
   double x ;
   char name[101] ;    // this is a string or char array


   printf ("Enter an integer value for n: ") ;
   scanf("%d", &n) ;   // don't forget the ampersand

   printf ("Enter a floating point value for x: ") ;
   scanf("%f", &x) ;  // double requires %lf, not %f

   printf ("Enter your first name (no spaces): ") ;
   scanf("%100s", name) ;

   printf ("Hello %s, you typed in %d for n and %f for x.\n", name, n, x) ;

   return 0 ;   // 0 means no error to report
}